494. Target Sum
At a Glance
- Topic: dp-2d
- Pattern: Dynamic Programming (subset sum / knapsack reformulation)
- Difficulty: Medium
- Companies: Facebook, Amazon, Google, Microsoft, Bloomberg
- Frequency: High
- LeetCode: 494
Problem (one-liner)
Assign + or - before each integer in nums so that the resulting expression equals target. Count how many assignments work. Input: nums, target. Output: number of ways.
Recognition Cues
- “Assign signs” / “build sum” with +/- each element
- Reformulate: find subset
positivesuch thatsum(positive) - sum(rest) = target - Let
total = sum(nums). Then2 * sum(positive) = target + total, so(target + total)must be even and non-negative.
Diagram
At-a-glance flow (replace with problem-specific Mermaid as you refine this note). camelCase node IDs; no spaces in IDs.
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Approaches
- Brute force —
2^nsign assignments. - Better — DP map from achievable sums —
O(n * sum)time. - Optimal — reduce to “number of subsets summing to
(target + total) / 2” with 0/1 style DP —O(n * subsetSum)time /O(subsetSum)space. <- pick this in interview.
Optimal Solution
Go
package main
func findTargetSumWaysTable(nums []int, target int) int {
total := 0
for _, value := range nums {
total += value
}
sumPositive := target + total
if sumPositive < 0 || sumPositive%2 == 1 {
return 0
}
subsetSum := sumPositive / 2
ways := make([][]int, len(nums)+1)
for index := range ways {
ways[index] = make([]int, subsetSum+1)
}
ways[0][0] = 1
for itemIndex := 1; itemIndex <= len(nums); itemIndex++ {
value := nums[itemIndex-1]
for sum := 0; sum <= subsetSum; sum++ {
ways[itemIndex][sum] = ways[itemIndex-1][sum]
if sum >= value {
ways[itemIndex][sum] += ways[itemIndex-1][sum-value]
}
}
}
return ways[len(nums)][subsetSum]
}
func findTargetSumWays(nums []int, target int) int {
total := 0
for _, value := range nums {
total += value
}
sumPositive := target + total
if sumPositive < 0 || sumPositive%2 == 1 {
return 0
}
subsetSum := sumPositive / 2
ways := make([]int, subsetSum+1)
ways[0] = 1
for _, value := range nums {
for sum := subsetSum; sum >= value; sum-- {
ways[sum] += ways[sum-value]
}
}
return ways[subsetSum]
}JavaScript
function findTargetSumWaysTable(nums, target) {
let total = 0;
for (const value of nums) {
total += value;
}
const sumPositive = target + total;
if (sumPositive < 0 || sumPositive % 2 === 1) return 0;
const subsetSum = sumPositive / 2;
const ways = Array.from({ length: nums.length + 1 }, () =>
new Array(subsetSum + 1).fill(0)
);
ways[0][0] = 1;
for (let itemIndex = 1; itemIndex <= nums.length; itemIndex++) {
const value = nums[itemIndex - 1];
for (let sum = 0; sum <= subsetSum; sum++) {
ways[itemIndex][sum] = ways[itemIndex - 1][sum];
if (sum >= value) {
ways[itemIndex][sum] += ways[itemIndex - 1][sum - value];
}
}
}
return ways[nums.length][subsetSum];
}
function findTargetSumWays(nums, target) {
let total = 0;
for (const value of nums) {
total += value;
}
const sumPositive = target + total;
if (sumPositive < 0 || sumPositive % 2 === 1) return 0;
const subsetSum = sumPositive / 2;
const ways = new Array(subsetSum + 1).fill(0);
ways[0] = 1;
for (const value of nums) {
for (let sum = subsetSum; sum >= value; sum--) {
ways[sum] += ways[sum - value];
}
}
return ways[subsetSum];
}Walkthrough
nums = [1,1,1,1,1], target = 3
total = 5, sumPositive = 8, subsetSum = 4. Count subsets summing to 4 from five 1s → C(5,4)=5.
Edge Cases
targetmagnitude exceeds achievable range →0- Zeros in
numsmultiply ways (handle via DP naturally)
Pitfalls
- Using reformulation without parity check
- Integer overflow in
target + total
Similar Problems
- 416. Partition Equal Subset Sum — feasibility version of subset sum.
- 518. Coin Change 2 — counting compositions with different semantics.
Variants
- Output one assignment → backtrack with memo.
Mind-Map Tags
#subset-sum #sign-assignment #01-knapsack-count #medium
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