236. Lowest Common Ancestor of a Binary Tree
At a Glance
- Topic: Tree
- Pattern: Analyze Pattern
- Difficulty: Medium
- LeetCode: 236
Problem Statement
Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (where we allow a node to be a descendant of itself).”
Example 1:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 1 Output: 3 Explanation: The LCA of nodes 5 and 1 is 3.
Example 2:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 4 Output: 5 Explanation: The LCA of nodes 5 and 4 is 5, since a node can be a descendant of itself according to the LCA definition.
Example 3:
Input: root = [1,2], p = 1, q = 2 Output: 1
Constraints:
The number of nodes in the tree is in the range [2, 105].
-109 <= Node.val <= 109
All Node.val are unique.
p != q
p and q will exist in the tree.Approach & Solution Steps
Use a recursive DFS approach. If the current node is null, or matches p or q, return it. Recursively search left and right subtrees. If both return non-null, the current node is the LCA. If only one returns non-null, pass it up.
Optimal JS Solution
function lowestCommonAncestor(root, p, q) {
if (!root || root === p || root === q) return root;
const left = lowestCommonAncestor(root.left, p, q);
const right = lowestCommonAncestor(root.right, p, q);
if (left && right) return root;
return left ? left : right;
}Edge Cases & Pitfalls
- Always consider empty or null inputs.
- Watch out for off-by-one index errors.
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