104. Maximum Depth of Binary Tree
At a Glance
- Topic: Binary Tree
- Pattern: DFS
- Difficulty: Easy
- LeetCode: 104
Problem Statement
Given the root of a binary tree, return its maximum depth.
A binary tree's maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Example 1:
Input: root = [3,9,20,null,null,15,7] Output: 3
Example 2:
Input: root = [1,null,2] Output: 2
Constraints:
The number of nodes in the tree is in the range [0, 104].
-100 <= Node.val <= 100Approach & Solution Steps
Use a recursive DFS approach. The depth of a node is 1 plus the maximum depth of its left and right subtrees.
Optimal JS Solution
function maxDepth(root) {
if (!root) return 0;
return Math.max(maxDepth(root.left), maxDepth(root.right)) + 1;
}Edge Cases & Pitfalls
- Always consider empty or null inputs.
- Watch out for off-by-one index errors.
Mark this page when you finish learning it.
Last updated on
Spotted something unclear or wrong on this page?